MATH UPDATE: in order to keep up with modern design standards, we are rounding the vertex of f(x)=|x|. please adjust your calculations accordingly.
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bluesky users: follow @ap.brid.gy hey there! i'm doskel; i like radios, bikes, climbing, inline skating, computers, freerunning, and making things that bridge the gaps between them. i'm doskel on doskel.net on basically every platform under the sun. if you find one i'm not on, let me know. i want to be there. the doskel strategy: unbreakable positivity with maybe a hint of ego cave johnson, we're done here alt: @doskel |
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\{x \in (\frac{-r}{\sqrt{2}},\frac{+r}{\sqrt{2}}):r\sqrt{2}-\sqrt{r^2-x^2},|x|\}
@doskel hyperbola
f(x) = (1+x^2)^(1/2)